4x^2+4x-120=121

Solution for 4x^2+4x-120=121 equation:

4x^2+4x-120=121

We move all terms to the left:

4x^2+4x-120-(121)=0

We add all the numbers together, and all the variables

4x^2+4x-241=0

a = 4; b = 4; c = -241;
Δ = b2-4ac
Δ = 42-4·4·(-241)
Δ = 3872
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3872}=\sqrt{1936*2}=\sqrt{1936}*\sqrt{2}=44\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-44\sqrt{2}}{2*4}=\frac{-4-44\sqrt{2}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+44\sqrt{2}}{2*4}=\frac{-4+44\sqrt{2}}{8}
$